一个4维数组是由3维数组组成的数组。

算法

Begin.
   Declare the variables.
   Declare the array elements.
   Take the no of elements as input.
   Take the elements as input.
   Print the elements stored in array.
End.

这是一个4D数组的示例。

#include<iostream>
using namespace std;
int main() {
   int a[2][2][3][2];
   cout << "Enter the elements of array: \n";
   for(int i = 0; i < 2; ++i) {
      for (int j = 0; j < 2; ++j) {
         for(int k = 0; k < 3; ++k ) {
            for(int l = 0; l < 2; ++l ) {
               cin >> a[i][j][k][l];
            }
         }
      }
   }
   cout<<"\narray elements are stored as:"<<endl;
   for(int i = 0; i < 2; ++i) {
      for (int j = 0; j < 2; ++j) {
         for(int k = 0; k < 3; ++k) {
            for(int l = 0; l < 2; ++l) {
               cout << "a[" << i << "][" << j << "][" << k << "] [" <<l<<"]= " << a[i][j][k][l] << endl;
            }
         }
      }
   }
   return 0;
}

输出

Enter the elements of array:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24

array elements are stored as:
a[0][0][0] [0]= 1
a[0][0][0] [1]= 2
a[0][0][1] [0]= 3
a[0][0][1] [1]= 4
a[0][0][2] [0]= 5
a[0][0][2] [1]= 6
a[0][1][0] [0]= 7
a[0][1][0] [1]= 8
a[0][1][1] [0]= 9
a[0][1][1] [1]= 10
a[0][1][2] [0]= 11
a[0][1][2] [1]= 12
a[1][0][0] [0]= 13
a[1][0][0] [1]= 14
a[1][0][1] [0]= 15
a[1][0][1] [1]= 16
a[1][0][2] [0]= 17
a[1][0][2] [1]= 18
a[1][1][0] [0]= 19
a[1][1][0] [1]= 20
a[1][1][1] [0]= 21
a[1][1][1] [1]= 22
a[1][1][2] [0]= 23
a[1][1][2] [1]= 24